3.1240 \(\int \cos ^6(c+d x) \sin ^4(c+d x) (a+b \sin (c+d x))^2 \, dx\)

Optimal. Leaf size=250 \[ \frac{\left (12 a^2+25 b^2\right ) \sin (c+d x) \cos ^9(c+d x)}{120 d}-\frac{\left (44 a^2+45 b^2\right ) \sin (c+d x) \cos ^7(c+d x)}{320 d}+\frac{\left (12 a^2+5 b^2\right ) \sin (c+d x) \cos ^5(c+d x)}{1920 d}+\frac{\left (12 a^2+5 b^2\right ) \sin (c+d x) \cos ^3(c+d x)}{1536 d}+\frac{\left (12 a^2+5 b^2\right ) \sin (c+d x) \cos (c+d x)}{1024 d}+\frac{x \left (12 a^2+5 b^2\right )}{1024}-\frac{2 a b \cos ^{11}(c+d x)}{11 d}+\frac{4 a b \cos ^9(c+d x)}{9 d}-\frac{2 a b \cos ^7(c+d x)}{7 d}-\frac{b^2 \sin (c+d x) \cos ^{11}(c+d x)}{12 d} \]

[Out]

((12*a^2 + 5*b^2)*x)/1024 - (2*a*b*Cos[c + d*x]^7)/(7*d) + (4*a*b*Cos[c + d*x]^9)/(9*d) - (2*a*b*Cos[c + d*x]^
11)/(11*d) + ((12*a^2 + 5*b^2)*Cos[c + d*x]*Sin[c + d*x])/(1024*d) + ((12*a^2 + 5*b^2)*Cos[c + d*x]^3*Sin[c +
d*x])/(1536*d) + ((12*a^2 + 5*b^2)*Cos[c + d*x]^5*Sin[c + d*x])/(1920*d) - ((44*a^2 + 45*b^2)*Cos[c + d*x]^7*S
in[c + d*x])/(320*d) + ((12*a^2 + 25*b^2)*Cos[c + d*x]^9*Sin[c + d*x])/(120*d) - (b^2*Cos[c + d*x]^11*Sin[c +
d*x])/(12*d)

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Rubi [A]  time = 0.354725, antiderivative size = 250, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 9, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.31, Rules used = {2911, 2565, 270, 3200, 455, 1157, 385, 199, 203} \[ \frac{\left (12 a^2+25 b^2\right ) \sin (c+d x) \cos ^9(c+d x)}{120 d}-\frac{\left (44 a^2+45 b^2\right ) \sin (c+d x) \cos ^7(c+d x)}{320 d}+\frac{\left (12 a^2+5 b^2\right ) \sin (c+d x) \cos ^5(c+d x)}{1920 d}+\frac{\left (12 a^2+5 b^2\right ) \sin (c+d x) \cos ^3(c+d x)}{1536 d}+\frac{\left (12 a^2+5 b^2\right ) \sin (c+d x) \cos (c+d x)}{1024 d}+\frac{x \left (12 a^2+5 b^2\right )}{1024}-\frac{2 a b \cos ^{11}(c+d x)}{11 d}+\frac{4 a b \cos ^9(c+d x)}{9 d}-\frac{2 a b \cos ^7(c+d x)}{7 d}-\frac{b^2 \sin (c+d x) \cos ^{11}(c+d x)}{12 d} \]

Antiderivative was successfully verified.

[In]

Int[Cos[c + d*x]^6*Sin[c + d*x]^4*(a + b*Sin[c + d*x])^2,x]

[Out]

((12*a^2 + 5*b^2)*x)/1024 - (2*a*b*Cos[c + d*x]^7)/(7*d) + (4*a*b*Cos[c + d*x]^9)/(9*d) - (2*a*b*Cos[c + d*x]^
11)/(11*d) + ((12*a^2 + 5*b^2)*Cos[c + d*x]*Sin[c + d*x])/(1024*d) + ((12*a^2 + 5*b^2)*Cos[c + d*x]^3*Sin[c +
d*x])/(1536*d) + ((12*a^2 + 5*b^2)*Cos[c + d*x]^5*Sin[c + d*x])/(1920*d) - ((44*a^2 + 45*b^2)*Cos[c + d*x]^7*S
in[c + d*x])/(320*d) + ((12*a^2 + 25*b^2)*Cos[c + d*x]^9*Sin[c + d*x])/(120*d) - (b^2*Cos[c + d*x]^11*Sin[c +
d*x])/(12*d)

Rule 2911

Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((d_.)*sin[(e_.) + (f_.)*(x_)])^(n_)*((a_) + (b_.)*sin[(e_.) + (f_.)*
(x_)])^2, x_Symbol] :> Dist[(2*a*b)/d, Int[(g*Cos[e + f*x])^p*(d*Sin[e + f*x])^(n + 1), x], x] + Int[(g*Cos[e
+ f*x])^p*(d*Sin[e + f*x])^n*(a^2 + b^2*Sin[e + f*x]^2), x] /; FreeQ[{a, b, d, e, f, g, n, p}, x] && NeQ[a^2 -
b^2, 0]

Rule 2565

Int[(cos[(e_.) + (f_.)*(x_)]*(a_.))^(m_.)*sin[(e_.) + (f_.)*(x_)]^(n_.), x_Symbol] :> -Dist[(a*f)^(-1), Subst[
Int[x^m*(1 - x^2/a^2)^((n - 1)/2), x], x, a*Cos[e + f*x]], x] /; FreeQ[{a, e, f, m}, x] && IntegerQ[(n - 1)/2]
&&  !(IntegerQ[(m - 1)/2] && GtQ[m, 0] && LeQ[m, n])

Rule 270

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.), x_Symbol] :> Int[ExpandIntegrand[(c*x)^m*(a + b*x^n)^p,
x], x] /; FreeQ[{a, b, c, m, n}, x] && IGtQ[p, 0]

Rule 3200

Int[cos[(e_.) + (f_.)*(x_)]^(m_)*sin[(e_.) + (f_.)*(x_)]^(n_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]^2)^(p_.),
x_Symbol] :> With[{ff = FreeFactors[Tan[e + f*x], x]}, Dist[ff^(n + 1)/f, Subst[Int[(x^n*(a + (a + b)*ff^2*x^2
)^p)/(1 + ff^2*x^2)^((m + n)/2 + p + 1), x], x, Tan[e + f*x]/ff], x]] /; FreeQ[{a, b, e, f}, x] && IntegerQ[m/
2] && IntegerQ[n/2] && IntegerQ[p]

Rule 455

Int[(x_)^(m_)*((a_) + (b_.)*(x_)^2)^(p_)*((c_) + (d_.)*(x_)^2), x_Symbol] :> Simp[((-a)^(m/2 - 1)*(b*c - a*d)*
x*(a + b*x^2)^(p + 1))/(2*b^(m/2 + 1)*(p + 1)), x] + Dist[1/(2*b^(m/2 + 1)*(p + 1)), Int[(a + b*x^2)^(p + 1)*E
xpandToSum[2*b*(p + 1)*x^2*Together[(b^(m/2)*x^(m - 2)*(c + d*x^2) - (-a)^(m/2 - 1)*(b*c - a*d))/(a + b*x^2)]
- (-a)^(m/2 - 1)*(b*c - a*d), x], x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0] && LtQ[p, -1] && IGtQ[
m/2, 0] && (IntegerQ[p] || EqQ[m + 2*p + 1, 0])

Rule 1157

Int[((d_) + (e_.)*(x_)^2)^(q_)*((a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4)^(p_.), x_Symbol] :> With[{Qx = PolynomialQ
uotient[(a + b*x^2 + c*x^4)^p, d + e*x^2, x], R = Coeff[PolynomialRemainder[(a + b*x^2 + c*x^4)^p, d + e*x^2,
x], x, 0]}, -Simp[(R*x*(d + e*x^2)^(q + 1))/(2*d*(q + 1)), x] + Dist[1/(2*d*(q + 1)), Int[(d + e*x^2)^(q + 1)*
ExpandToSum[2*d*(q + 1)*Qx + R*(2*q + 3), x], x], x]] /; FreeQ[{a, b, c, d, e}, x] && NeQ[b^2 - 4*a*c, 0] && N
eQ[c*d^2 - b*d*e + a*e^2, 0] && IGtQ[p, 0] && LtQ[q, -1]

Rule 385

Int[((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_)), x_Symbol] :> -Simp[((b*c - a*d)*x*(a + b*x^n)^(p +
1))/(a*b*n*(p + 1)), x] - Dist[(a*d - b*c*(n*(p + 1) + 1))/(a*b*n*(p + 1)), Int[(a + b*x^n)^(p + 1), x], x] /
; FreeQ[{a, b, c, d, n, p}, x] && NeQ[b*c - a*d, 0] && (LtQ[p, -1] || ILtQ[1/n + p, 0])

Rule 199

Int[((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> -Simp[(x*(a + b*x^n)^(p + 1))/(a*n*(p + 1)), x] + Dist[(n*(p +
1) + 1)/(a*n*(p + 1)), Int[(a + b*x^n)^(p + 1), x], x] /; FreeQ[{a, b}, x] && IGtQ[n, 0] && LtQ[p, -1] && (In
tegerQ[2*p] || (n == 2 && IntegerQ[4*p]) || (n == 2 && IntegerQ[3*p]) || Denominator[p + 1/n] < Denominator[p]
)

Rule 203

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTan[(Rt[b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[b, 2]), x] /;
FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a, 0] || GtQ[b, 0])

Rubi steps

\begin{align*} \int \cos ^6(c+d x) \sin ^4(c+d x) (a+b \sin (c+d x))^2 \, dx &=(2 a b) \int \cos ^6(c+d x) \sin ^5(c+d x) \, dx+\int \cos ^6(c+d x) \sin ^4(c+d x) \left (a^2+b^2 \sin ^2(c+d x)\right ) \, dx\\ &=\frac{\operatorname{Subst}\left (\int \frac{x^4 \left (a^2+\left (a^2+b^2\right ) x^2\right )}{\left (1+x^2\right )^7} \, dx,x,\tan (c+d x)\right )}{d}-\frac{(2 a b) \operatorname{Subst}\left (\int x^6 \left (1-x^2\right )^2 \, dx,x,\cos (c+d x)\right )}{d}\\ &=-\frac{b^2 \cos ^{11}(c+d x) \sin (c+d x)}{12 d}-\frac{\operatorname{Subst}\left (\int \frac{-b^2+12 b^2 x^2-12 \left (a^2+b^2\right ) x^4}{\left (1+x^2\right )^6} \, dx,x,\tan (c+d x)\right )}{12 d}-\frac{(2 a b) \operatorname{Subst}\left (\int \left (x^6-2 x^8+x^{10}\right ) \, dx,x,\cos (c+d x)\right )}{d}\\ &=-\frac{2 a b \cos ^7(c+d x)}{7 d}+\frac{4 a b \cos ^9(c+d x)}{9 d}-\frac{2 a b \cos ^{11}(c+d x)}{11 d}+\frac{\left (12 a^2+25 b^2\right ) \cos ^9(c+d x) \sin (c+d x)}{120 d}-\frac{b^2 \cos ^{11}(c+d x) \sin (c+d x)}{12 d}+\frac{\operatorname{Subst}\left (\int \frac{-3 \left (4 a^2+5 b^2\right )+120 \left (a^2+b^2\right ) x^2}{\left (1+x^2\right )^5} \, dx,x,\tan (c+d x)\right )}{120 d}\\ &=-\frac{2 a b \cos ^7(c+d x)}{7 d}+\frac{4 a b \cos ^9(c+d x)}{9 d}-\frac{2 a b \cos ^{11}(c+d x)}{11 d}-\frac{\left (44 a^2+45 b^2\right ) \cos ^7(c+d x) \sin (c+d x)}{320 d}+\frac{\left (12 a^2+25 b^2\right ) \cos ^9(c+d x) \sin (c+d x)}{120 d}-\frac{b^2 \cos ^{11}(c+d x) \sin (c+d x)}{12 d}+\frac{\left (12 a^2+5 b^2\right ) \operatorname{Subst}\left (\int \frac{1}{\left (1+x^2\right )^4} \, dx,x,\tan (c+d x)\right )}{320 d}\\ &=-\frac{2 a b \cos ^7(c+d x)}{7 d}+\frac{4 a b \cos ^9(c+d x)}{9 d}-\frac{2 a b \cos ^{11}(c+d x)}{11 d}+\frac{\left (12 a^2+5 b^2\right ) \cos ^5(c+d x) \sin (c+d x)}{1920 d}-\frac{\left (44 a^2+45 b^2\right ) \cos ^7(c+d x) \sin (c+d x)}{320 d}+\frac{\left (12 a^2+25 b^2\right ) \cos ^9(c+d x) \sin (c+d x)}{120 d}-\frac{b^2 \cos ^{11}(c+d x) \sin (c+d x)}{12 d}+\frac{\left (12 a^2+5 b^2\right ) \operatorname{Subst}\left (\int \frac{1}{\left (1+x^2\right )^3} \, dx,x,\tan (c+d x)\right )}{384 d}\\ &=-\frac{2 a b \cos ^7(c+d x)}{7 d}+\frac{4 a b \cos ^9(c+d x)}{9 d}-\frac{2 a b \cos ^{11}(c+d x)}{11 d}+\frac{\left (12 a^2+5 b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{1536 d}+\frac{\left (12 a^2+5 b^2\right ) \cos ^5(c+d x) \sin (c+d x)}{1920 d}-\frac{\left (44 a^2+45 b^2\right ) \cos ^7(c+d x) \sin (c+d x)}{320 d}+\frac{\left (12 a^2+25 b^2\right ) \cos ^9(c+d x) \sin (c+d x)}{120 d}-\frac{b^2 \cos ^{11}(c+d x) \sin (c+d x)}{12 d}+\frac{\left (12 a^2+5 b^2\right ) \operatorname{Subst}\left (\int \frac{1}{\left (1+x^2\right )^2} \, dx,x,\tan (c+d x)\right )}{512 d}\\ &=-\frac{2 a b \cos ^7(c+d x)}{7 d}+\frac{4 a b \cos ^9(c+d x)}{9 d}-\frac{2 a b \cos ^{11}(c+d x)}{11 d}+\frac{\left (12 a^2+5 b^2\right ) \cos (c+d x) \sin (c+d x)}{1024 d}+\frac{\left (12 a^2+5 b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{1536 d}+\frac{\left (12 a^2+5 b^2\right ) \cos ^5(c+d x) \sin (c+d x)}{1920 d}-\frac{\left (44 a^2+45 b^2\right ) \cos ^7(c+d x) \sin (c+d x)}{320 d}+\frac{\left (12 a^2+25 b^2\right ) \cos ^9(c+d x) \sin (c+d x)}{120 d}-\frac{b^2 \cos ^{11}(c+d x) \sin (c+d x)}{12 d}+\frac{\left (12 a^2+5 b^2\right ) \operatorname{Subst}\left (\int \frac{1}{1+x^2} \, dx,x,\tan (c+d x)\right )}{1024 d}\\ &=\frac{\left (12 a^2+5 b^2\right ) x}{1024}-\frac{2 a b \cos ^7(c+d x)}{7 d}+\frac{4 a b \cos ^9(c+d x)}{9 d}-\frac{2 a b \cos ^{11}(c+d x)}{11 d}+\frac{\left (12 a^2+5 b^2\right ) \cos (c+d x) \sin (c+d x)}{1024 d}+\frac{\left (12 a^2+5 b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{1536 d}+\frac{\left (12 a^2+5 b^2\right ) \cos ^5(c+d x) \sin (c+d x)}{1920 d}-\frac{\left (44 a^2+45 b^2\right ) \cos ^7(c+d x) \sin (c+d x)}{320 d}+\frac{\left (12 a^2+25 b^2\right ) \cos ^9(c+d x) \sin (c+d x)}{120 d}-\frac{b^2 \cos ^{11}(c+d x) \sin (c+d x)}{12 d}\\ \end{align*}

Mathematica [A]  time = 1.38634, size = 202, normalized size = 0.81 \[ \frac{55440 a^2 \sin (2 (c+d x))-110880 a^2 \sin (4 (c+d x))-27720 a^2 \sin (6 (c+d x))+13860 a^2 \sin (8 (c+d x))+5544 a^2 \sin (10 (c+d x))+332640 a^2 d x-554400 a b \cos (c+d x)-184800 a b \cos (3 (c+d x))+55440 a b \cos (5 (c+d x))+39600 a b \cos (7 (c+d x))-6160 a b \cos (9 (c+d x))-5040 a b \cos (11 (c+d x))-51975 b^2 \sin (4 (c+d x))+10395 b^2 \sin (8 (c+d x))-1155 b^2 \sin (12 (c+d x))+166320 b^2 c+138600 b^2 d x}{28385280 d} \]

Antiderivative was successfully verified.

[In]

Integrate[Cos[c + d*x]^6*Sin[c + d*x]^4*(a + b*Sin[c + d*x])^2,x]

[Out]

(166320*b^2*c + 332640*a^2*d*x + 138600*b^2*d*x - 554400*a*b*Cos[c + d*x] - 184800*a*b*Cos[3*(c + d*x)] + 5544
0*a*b*Cos[5*(c + d*x)] + 39600*a*b*Cos[7*(c + d*x)] - 6160*a*b*Cos[9*(c + d*x)] - 5040*a*b*Cos[11*(c + d*x)] +
55440*a^2*Sin[2*(c + d*x)] - 110880*a^2*Sin[4*(c + d*x)] - 51975*b^2*Sin[4*(c + d*x)] - 27720*a^2*Sin[6*(c +
d*x)] + 13860*a^2*Sin[8*(c + d*x)] + 10395*b^2*Sin[8*(c + d*x)] + 5544*a^2*Sin[10*(c + d*x)] - 1155*b^2*Sin[12
*(c + d*x)])/(28385280*d)

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Maple [A]  time = 0.05, size = 237, normalized size = 1. \begin{align*}{\frac{1}{d} \left ({a}^{2} \left ( -{\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{3} \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{10}}-{\frac{3\,\sin \left ( dx+c \right ) \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{80}}+{\frac{\sin \left ( dx+c \right ) }{160} \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{5}+{\frac{5\, \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{4}}+{\frac{15\,\cos \left ( dx+c \right ) }{8}} \right ) }+{\frac{3\,dx}{256}}+{\frac{3\,c}{256}} \right ) +2\,ab \left ( -1/11\, \left ( \sin \left ( dx+c \right ) \right ) ^{4} \left ( \cos \left ( dx+c \right ) \right ) ^{7}-{\frac{4\, \left ( \sin \left ( dx+c \right ) \right ) ^{2} \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{99}}-{\frac{8\, \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{693}} \right ) +{b}^{2} \left ( -{\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{5} \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{12}}-{\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{3} \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{24}}-{\frac{\sin \left ( dx+c \right ) \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{64}}+{\frac{\sin \left ( dx+c \right ) }{384} \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{5}+{\frac{5\, \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{4}}+{\frac{15\,\cos \left ( dx+c \right ) }{8}} \right ) }+{\frac{5\,dx}{1024}}+{\frac{5\,c}{1024}} \right ) \right ) } \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cos(d*x+c)^6*sin(d*x+c)^4*(a+b*sin(d*x+c))^2,x)

[Out]

1/d*(a^2*(-1/10*sin(d*x+c)^3*cos(d*x+c)^7-3/80*sin(d*x+c)*cos(d*x+c)^7+1/160*(cos(d*x+c)^5+5/4*cos(d*x+c)^3+15
/8*cos(d*x+c))*sin(d*x+c)+3/256*d*x+3/256*c)+2*a*b*(-1/11*sin(d*x+c)^4*cos(d*x+c)^7-4/99*sin(d*x+c)^2*cos(d*x+
c)^7-8/693*cos(d*x+c)^7)+b^2*(-1/12*sin(d*x+c)^5*cos(d*x+c)^7-1/24*sin(d*x+c)^3*cos(d*x+c)^7-1/64*sin(d*x+c)*c
os(d*x+c)^7+1/384*(cos(d*x+c)^5+5/4*cos(d*x+c)^3+15/8*cos(d*x+c))*sin(d*x+c)+5/1024*d*x+5/1024*c))

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Maxima [A]  time = 1.01978, size = 185, normalized size = 0.74 \begin{align*} \frac{2772 \,{\left (32 \, \sin \left (2 \, d x + 2 \, c\right )^{5} + 120 \, d x + 120 \, c + 5 \, \sin \left (8 \, d x + 8 \, c\right ) - 40 \, \sin \left (4 \, d x + 4 \, c\right )\right )} a^{2} - 81920 \,{\left (63 \, \cos \left (d x + c\right )^{11} - 154 \, \cos \left (d x + c\right )^{9} + 99 \, \cos \left (d x + c\right )^{7}\right )} a b + 1155 \,{\left (4 \, \sin \left (4 \, d x + 4 \, c\right )^{3} + 120 \, d x + 120 \, c + 9 \, \sin \left (8 \, d x + 8 \, c\right ) - 48 \, \sin \left (4 \, d x + 4 \, c\right )\right )} b^{2}}{28385280 \, d} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^6*sin(d*x+c)^4*(a+b*sin(d*x+c))^2,x, algorithm="maxima")

[Out]

1/28385280*(2772*(32*sin(2*d*x + 2*c)^5 + 120*d*x + 120*c + 5*sin(8*d*x + 8*c) - 40*sin(4*d*x + 4*c))*a^2 - 81
920*(63*cos(d*x + c)^11 - 154*cos(d*x + c)^9 + 99*cos(d*x + c)^7)*a*b + 1155*(4*sin(4*d*x + 4*c)^3 + 120*d*x +
120*c + 9*sin(8*d*x + 8*c) - 48*sin(4*d*x + 4*c))*b^2)/d

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Fricas [A]  time = 1.99478, size = 486, normalized size = 1.94 \begin{align*} -\frac{645120 \, a b \cos \left (d x + c\right )^{11} - 1576960 \, a b \cos \left (d x + c\right )^{9} + 1013760 \, a b \cos \left (d x + c\right )^{7} - 3465 \,{\left (12 \, a^{2} + 5 \, b^{2}\right )} d x + 231 \,{\left (1280 \, b^{2} \cos \left (d x + c\right )^{11} - 128 \,{\left (12 \, a^{2} + 25 \, b^{2}\right )} \cos \left (d x + c\right )^{9} + 48 \,{\left (44 \, a^{2} + 45 \, b^{2}\right )} \cos \left (d x + c\right )^{7} - 8 \,{\left (12 \, a^{2} + 5 \, b^{2}\right )} \cos \left (d x + c\right )^{5} - 10 \,{\left (12 \, a^{2} + 5 \, b^{2}\right )} \cos \left (d x + c\right )^{3} - 15 \,{\left (12 \, a^{2} + 5 \, b^{2}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{3548160 \, d} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^6*sin(d*x+c)^4*(a+b*sin(d*x+c))^2,x, algorithm="fricas")

[Out]

-1/3548160*(645120*a*b*cos(d*x + c)^11 - 1576960*a*b*cos(d*x + c)^9 + 1013760*a*b*cos(d*x + c)^7 - 3465*(12*a^
2 + 5*b^2)*d*x + 231*(1280*b^2*cos(d*x + c)^11 - 128*(12*a^2 + 25*b^2)*cos(d*x + c)^9 + 48*(44*a^2 + 45*b^2)*c
os(d*x + c)^7 - 8*(12*a^2 + 5*b^2)*cos(d*x + c)^5 - 10*(12*a^2 + 5*b^2)*cos(d*x + c)^3 - 15*(12*a^2 + 5*b^2)*c
os(d*x + c))*sin(d*x + c))/d

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Sympy [A]  time = 90.7959, size = 656, normalized size = 2.62 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)**6*sin(d*x+c)**4*(a+b*sin(d*x+c))**2,x)

[Out]

Piecewise((3*a**2*x*sin(c + d*x)**10/256 + 15*a**2*x*sin(c + d*x)**8*cos(c + d*x)**2/256 + 15*a**2*x*sin(c + d
*x)**6*cos(c + d*x)**4/128 + 15*a**2*x*sin(c + d*x)**4*cos(c + d*x)**6/128 + 15*a**2*x*sin(c + d*x)**2*cos(c +
d*x)**8/256 + 3*a**2*x*cos(c + d*x)**10/256 + 3*a**2*sin(c + d*x)**9*cos(c + d*x)/(256*d) + 7*a**2*sin(c + d*
x)**7*cos(c + d*x)**3/(128*d) + a**2*sin(c + d*x)**5*cos(c + d*x)**5/(10*d) - 7*a**2*sin(c + d*x)**3*cos(c + d
*x)**7/(128*d) - 3*a**2*sin(c + d*x)*cos(c + d*x)**9/(256*d) - 2*a*b*sin(c + d*x)**4*cos(c + d*x)**7/(7*d) - 8
*a*b*sin(c + d*x)**2*cos(c + d*x)**9/(63*d) - 16*a*b*cos(c + d*x)**11/(693*d) + 5*b**2*x*sin(c + d*x)**12/1024
+ 15*b**2*x*sin(c + d*x)**10*cos(c + d*x)**2/512 + 75*b**2*x*sin(c + d*x)**8*cos(c + d*x)**4/1024 + 25*b**2*x
*sin(c + d*x)**6*cos(c + d*x)**6/256 + 75*b**2*x*sin(c + d*x)**4*cos(c + d*x)**8/1024 + 15*b**2*x*sin(c + d*x)
**2*cos(c + d*x)**10/512 + 5*b**2*x*cos(c + d*x)**12/1024 + 5*b**2*sin(c + d*x)**11*cos(c + d*x)/(1024*d) + 85
*b**2*sin(c + d*x)**9*cos(c + d*x)**3/(3072*d) + 33*b**2*sin(c + d*x)**7*cos(c + d*x)**5/(512*d) - 33*b**2*sin
(c + d*x)**5*cos(c + d*x)**7/(512*d) - 85*b**2*sin(c + d*x)**3*cos(c + d*x)**9/(3072*d) - 5*b**2*sin(c + d*x)*
cos(c + d*x)**11/(1024*d), Ne(d, 0)), (x*(a + b*sin(c))**2*sin(c)**4*cos(c)**6, True))

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Giac [A]  time = 1.30758, size = 305, normalized size = 1.22 \begin{align*} \frac{1}{1024} \,{\left (12 \, a^{2} + 5 \, b^{2}\right )} x - \frac{a b \cos \left (11 \, d x + 11 \, c\right )}{5632 \, d} - \frac{a b \cos \left (9 \, d x + 9 \, c\right )}{4608 \, d} + \frac{5 \, a b \cos \left (7 \, d x + 7 \, c\right )}{3584 \, d} + \frac{a b \cos \left (5 \, d x + 5 \, c\right )}{512 \, d} - \frac{5 \, a b \cos \left (3 \, d x + 3 \, c\right )}{768 \, d} - \frac{5 \, a b \cos \left (d x + c\right )}{256 \, d} - \frac{b^{2} \sin \left (12 \, d x + 12 \, c\right )}{24576 \, d} + \frac{a^{2} \sin \left (10 \, d x + 10 \, c\right )}{5120 \, d} - \frac{a^{2} \sin \left (6 \, d x + 6 \, c\right )}{1024 \, d} + \frac{a^{2} \sin \left (2 \, d x + 2 \, c\right )}{512 \, d} + \frac{{\left (4 \, a^{2} + 3 \, b^{2}\right )} \sin \left (8 \, d x + 8 \, c\right )}{8192 \, d} - \frac{{\left (32 \, a^{2} + 15 \, b^{2}\right )} \sin \left (4 \, d x + 4 \, c\right )}{8192 \, d} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^6*sin(d*x+c)^4*(a+b*sin(d*x+c))^2,x, algorithm="giac")

[Out]

1/1024*(12*a^2 + 5*b^2)*x - 1/5632*a*b*cos(11*d*x + 11*c)/d - 1/4608*a*b*cos(9*d*x + 9*c)/d + 5/3584*a*b*cos(7
*d*x + 7*c)/d + 1/512*a*b*cos(5*d*x + 5*c)/d - 5/768*a*b*cos(3*d*x + 3*c)/d - 5/256*a*b*cos(d*x + c)/d - 1/245
76*b^2*sin(12*d*x + 12*c)/d + 1/5120*a^2*sin(10*d*x + 10*c)/d - 1/1024*a^2*sin(6*d*x + 6*c)/d + 1/512*a^2*sin(
2*d*x + 2*c)/d + 1/8192*(4*a^2 + 3*b^2)*sin(8*d*x + 8*c)/d - 1/8192*(32*a^2 + 15*b^2)*sin(4*d*x + 4*c)/d